Friday, March 29, 2013
Thursday, March 28, 2013
Wednesday, December 26, 2012
Rationalizing Imaginary Denominators
When dealing with fractions with imaginary denominators, one must express this as a complex number in a+bi form.
For example:
17 - 3i
10 + 7i
1) Multiply by the conjugate of the denominator over itself (fraction equals
17 - 3i * (10 - 7i)
10 + 7i (10 - 7i)
170 - 119i - 30i + 21i²
100 -70i + 70i + 49i²
3)Multiply top by top, bottom by bottom.
170 - 149i + 21i²
100 + 49i²
4)Combine the imaginary terms. They (i)
cancels out in the denominator.
170 - 149i - 21
100 + 49
5) Combine constant terms on top and bottom.
149 -149i
149
6)Split apart into a+bi form.
149 - 149 i
149 149
1 - i
For example:
17 - 3i
10 + 7i
1) Multiply by the conjugate of the denominator over itself (fraction equals
10 + 7i (10 - 7i)
2)Foil. FOIL the top and FOIL the bottom.
170 - 119i - 30i + 21i²
100 -70i + 70i + 49i²
3)Multiply top by top, bottom by bottom.
170 - 149i + 21i²
100 + 49i²
4)Combine the imaginary terms. They (i)
cancels out in the denominator.
170 - 149i - 21
100 + 49
5) Combine constant terms on top and bottom.
149 -149i
149
6)Split apart into a+bi form.
149 - 149 i
149 149
1 - i
Finding the roots of a parabola.
To find the roots of a parabola is fairly easy. Its all about the formulas.
Questions can be asked like this.
Determine the roots of the equationx2−2x−3=0 .
Questions can be asked like this.
Determine the roots of the equation
*The trick is to see whether an equation is factorable or not.
x^2 - 2x - 3 = 0 Factorable.
(x - 3) (x + 1) BAM!
Now find the roots.
x - 3 = 0 x + 1 = 0
x = 3 x = -1
The roots of the equation are 3 and -1.
Now if you get an equation that isn`t factorable like this -x^2 + 4x -3 = 0
Use the quadratic formula.
-----------------------------------------
-4 + or - √ 4^2 - 4(-1)(-3)
_____________________
2(-1)
-4 + or - √ 16 -12
_____________________
-2
-4 + or - √ 4 -4 + or - 2
_________ __________
-2 -2
-4 + 2 or -4 - 2
__________________________________________
-2 -2
-2 -6
__ ____
-2 -2
ROOTS are 1 and 3. DONE!
Systems of equations :$
*Systems of equations is asked when there are two equations. One must use both to find a coordinate; x and y.
*This is called solving linear systems algebraically.
Solve the system of equations 2x - 3y = 23 +3y=23and -x- 6y= -4
by combining the equations.
*This is called solving linear systems algebraically.
Solve the system of equations 2x - 3y = 23
by combining the equations.
1) First eliminate x.
2x - 3y = 23 -x - 6y = -4
Use both 2 and -1, to eliminate x.
1(2x - 3y = 23) 2( -x - 6y = -4) Distribute.
2x - 3y = 23
-2x - 12y = -8 2)Make sure to eliminate x, one is positive and one is negative.
____________
0x - 15y = 15
_________
-15 -15
y = -1 3) Now use y to find x. Plug in -1 to an easy equation.
2x - 3(-1) = 23
2x + 3 = 23
-3 -3
__________
2x = 20
______
2
x = 10
(10,-1)
Done!
Sunday, December 16, 2012
Simplifying Expressions with Rational Exponents =}
Rational exponents can be turned into radicals.
x^1/2 = √x
x^1/3 = 3√x
x^1/4 = 4√x
Examples:
1) 27^1/3 = 3√27 = 3√33 = 3
2) 12^1/2 * 3^1/2 = √12 * √3 = √36 = 6
3) 16^1/3 * 4^1/3 = 3√16 * 3√4 = 3√64 = 4

Remember Simplifying:
√2² x² y² z² = 2xyz
x3 x 4 = x7
More Examples:
1) (x^4 y ^6 z^8) ^1/2
x^4/2 y^6/2 z^8/2
x² y3 z 4
2) 4^3/2
(4^1/2)^3
(2)^3
8
3) (4^3)^1/2
64^1/2
√64
8
x^1/2 = √x
x^1/3 = 3√x
x^1/4 = 4√x
Examples:
1) 27^1/3 = 3√27 = 3√33 = 3
2) 12^1/2 * 3^1/2 = √12 * √3 = √36 = 6
3) 16^1/3 * 4^1/3 = 3√16 * 3√4 = 3√64 = 4
Remember Simplifying:
√2² x² y² z² = 2xyz
x3 x 4 = x7
More Examples:
1) (x^4 y ^6 z^8) ^1/2
x^4/2 y^6/2 z^8/2
x² y3 z 4
2) 4^3/2
(4^1/2)^3
(2)^3
8
3) (4^3)^1/2
64^1/2
√64
8
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